一、Floyd-Warshall算法
介绍
Floyd-Warshall算法(英语:Floyd-Warshall algorithm),中文亦称弗洛伊德算法或佛洛依德算法,是解决任意两点间的最短路径的一种算法,可以正确处理有向图或负权(但不可存在负权回路)的最短路径问题,同时也被用于计算有向图的闭包传递。
原理
其本质为动态规划,给定有向图图 G = ( V , E ) G = (V, E) G=(V,E),其中 V ( v e r t i c e s ) V(vertices) V(vertices)为顶点数, E ( e d g e s ) E(edges) E(edges)为边数,并给出初始权重矩阵 w [ i ] [ j ] w[i][j] w[i][j],表示顶点 i → j i \rightarrow j i→j的权重,其表达式为:
w i , j = { weight of edge ( i , j ) if ( i , j ) ∈ E ; ∞ if ( i , j ) ∉ E . \left.w_{i,j}=\left\{\begin{array}{ll}\text{weight of edge}\left(i,j\right)&\text{if}\left(i,j\right)\in E;\\\infty&\text{if}\left(i,j\right)\notin E.\end{array}\right.\right. wi,j={weight of edge(i,j)∞if(i,j)∈E;if(i,j)∈/E.
即,对于 i → j i \rightarrow j i→j未连通的边通常设置为一个无穷大的数 I N F INF INF;对于动态规划算法需要定义状态 D i , j , k D_{i,j,k} Di,j,k:从 i i i到 j j j只以( 1.. k 1..k 1..k)集合中的节点为中间节点的最短路径的长度;则可分为以下2种情况讨论:
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如果最短路经过点 k k k: D i , j , k = D i , k , k − 1 + D k , j , k − 1 . D_{i,j,k}=D_{i,k,k-1}+D_{k,j,k-1}. Di,j,k=Di,k,k−1+Dk,j,k−1.
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若最短路径不经过点 k k k: D i , j , k = D i , j , k − 1 。 D_{i,j,k}=D_{i,j,k-1\text{ 。 }} Di,j,k=Di,j,k−1 。
若不能理解 k − 1 k - 1 k−1的含义,则可理解为下一层 k k k的状态需要上一层 k − 1 k - 1 k−1推导出(因为要逐个枚举中间节点,例如 D 1 , 3 = D 1 , 2 + D 2 , 3 D_{1,3} = D_{1,2} + D_{2,3} D1,3=D1,2+D2,3,那么需要保证 D 1 , 2 , D 2 , 3 D_{1,2},D_{2,3} D1,2,D2,3是对应的最短距离,才能导致 D 1 , 3 D_{1,3} D1,3是1号节点到3号节点的最短距离)即第 k k k层状态依赖于第 k − 1 k-1 k−1层状态,故不可对 k k k层循环做并行化处理;最后可以得到状态转移方程:
D i , j , k = min ( D i , j , k − 1 , D i , k , k − 1 + D k , j , k − 1 ) D_{i,j,k}=\min(D_{i,j,k-1},D_{i,k,k-1}+D_{k,j,k-1}) Di,j,k=min(Di,j,k−1,Di,k,k−1+Dk,j,k−1)
在实际算法中,为了节约空间,可以直接在原来空间上进行迭代,这样空间可降至二维。
分析
- 时间复杂度: O ( V 3 ) O(V^3) O(V3),其中 V V V是点集,对于 i , j i,j i,j两层for循环可使用OpenMP优化到线性
- 空间复杂度: O ( V 2 ) O(V^2) O(V2)
二、CPU-GPU并行化Floyd-APSP算法
为了求到全部的最短路径,不仅需要计算最短路径距离矩阵 D D D,还需要计算最短路径构造矩阵 C C C。其中 C C C矩阵的定义为:如果在顶点 i i i和顶点 j j j之间至少存在一条最短路径,则 C i , j C_{i,j} Ci,j表示最短路径上编号最高的中间顶点,否则为undefined (NULL)。构造矩阵的初值都是未定义的,用数学表示如下:
c i , j ( k ) = { NULL i f k = 0 ; k i f k ≥ 1 a n d d i , j ( k − 1 ) > d i , k ( k − 1 ) + d k , j ( k − 1 ) ; c i , j ( k − 1 ) otherwise. , \left.c_{i,j}^{(k)}=\left\{\begin{array}{ll}\text{NULL}&\mathrm{if~}k=0;\\k&\mathrm{if~}k\geq1\mathrm{~and~}d_{i,j}^{(k-1)}>d_{i,k}^{(k-1)}+d_{k,j}^{(k-1)};\\c_{i,j}^{(k-1)}&\text{otherwise.}\end{array}\right.\right., ci,j(k)=⎩ ⎨ ⎧NULLkci,j(k−1)if k=0;if k≥1 and di,j(k−1)>di,k(k−1)+dk,j(k−1);otherwise.,
其中 C i , j k − 1 C_{i,j}^{k-1} Ci,jk−1与上相同,由于下一层受到上一层的制约,为递推关系。
Algorithm1: Floyd-Warshall
- Floyd-Warshall算法用于计算最短路径距离矩阵
D
i
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j
D_{i,j}
Di,j和最短路径构造矩阵
C
i
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j
C_{i,j}
Ci,j
Algorithm2:
- 输出一对顶点
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i
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j
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(i, j)
(i,j)之间最短路径的中间顶点的递归过程
可以想象为二叉树,一边是往左子树遍历,一边是往右子树遍历,即左根右的中序遍历。
分块联合算法
- 该算法是为在CPU-GPU混合系统上实现高GPU利用率的快速APSP解决方案而设计的。
在分块联合算法中,将 n × n n \times n n×n的距离矩阵 D i , j D_{i,j} Di,j和构造矩阵 C i , j C_{i,j} Ci,j划分为 b × b b \times b b×b的子矩阵的分块,其中 b b b为分块因子,为以下问题讨论方便,假设 n % b = = 0 n \% b ==0 n%b==0,即 n n n能整除 b b b,并在每个块内有定义 A I , J = a [ i , j ] A_{I, J} = a[i, j] AI,J=a[i,j]来标识块索引为 ( I , J ) (I,J) (I,J)的子矩阵,用数学符号表示为:
1 ≤ I , J ≤ [ n b ] , 1 ≤ i , j ≤ b 1 \leq I, J \leq [\frac{n}{b}] , \\ 1 \leq i,j \leq b 1≤I,J≤[bn],1≤i,j≤b
如下图所示,展现了 n = 12 n = 12 n=12矩阵的示例,其中 b = 3 b=3 b=3
Algorithm3
- 针对APSP问题的分块联合算法
将该算法划分4个阶段为:
- 首先将 n × n n \times n n×n的矩阵分解为长度为 [ n b ] × [ n b ] [\frac{n}{b}] \times [\frac{n}{b}] [bn]×[bn]的以 b × b b \times b b×b的矩阵,并外层枚举节点 ( K , K ) (K, K) (K,K),其中 1 ≤ K ≤ [ n b ] 1 \leq K \leq [\frac{n}{b}] 1≤K≤[bn],并在子矩阵 b × b b \times b b×b中使用Floyd-WarShall方法,求解 D K , K , C K , K D_{K, K}, C_{K,K} DK,K,CK,K。
- 对节点 ( K , K ) (K, K) (K,K)所在的第 K K K列进行MMA即矩阵乘法加法操作
- 对节点 ( K , K ) (K, K) (K,K)所在的第 K K K行进行MMA即矩阵乘法加法操作
- 对于除以上涉及到的剩余节点
Algorithm4
- APSP子问题的阻塞联合算法
- 区别在于:算法4的4-16行运行在GPU中,算法4的合并操作17-20运行在CPU中。
Algorithm5
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子分块联合APSP的矩阵-矩阵""乘-加"算法
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代数中的MMA算法可以扩展为同时计算路径矩阵 D i , j D_{i,j} Di,j和构造矩阵 C i , j C_{i,j} Ci,j
z i , j ← min ( z i , j , ∑ k = 1 b x i , k + y k , j ) z_{i,j} \leftarrow \min(z_{i,j}, \sum_{k=1}^b x_{i,k}+y_{k,j}) zi,j←min(zi,j,k=1∑bxi,k+yk,j)
其中, z i , j z_{i,j} zi,j为 b × b b \times b b×b的子矩阵。
Algorithm6
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阶段2-阶段4可以使用矩阵乘法更新,在本问题中,就是极小加代数。极小加代数的乘法和加法是分离执行的,极小加操作(MINPLUS)是运行在GPU中,矩阵加(MMA)运行在CPU中。
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这个操作减少了 Z , C Z,C Z,C从CPU到GPU的数据传输,也就允许了CPU和GPU之间的高速通信。
Code
- 以下代码均来自:https://github.com/EricLu1218/Parallel_Programming
模拟GPU的串行
#include
#include const int INF = ((1 << 30) - 1); const int V = 50010; void input(char *inFileName); void output(char *outFileName); void block_FW(int B); int ceil(int a, int b); void cal(int B, int Round, int block_start_x, int block_start_y, int block_width, int block_height); int n, m; static int Dist[V][V]; int main(int argc, char *argv[]) { input(argv[1]); int B = 512; block_FW(B); output(argv[2]); return 0; } void input(char *infile) { FILE *file = fopen(infile, "rb"); fread(&n, sizeof(int), 1, file); fread(&m, sizeof(int), 1, file); for (int i = 0; i < n; ++i) { for (int j = 0; j < n; ++j) { if (i == j) { Dist[i][j] = 0; } else { Dist[i][j] = INF; } } } int pair[3]; for (int i = 0; i < m; ++i) { fread(pair, sizeof(int), 3, file); Dist[pair[0]][pair[1]] = pair[2]; } fclose(file); } void output(char *outFileName) { FILE *outfile = fopen(outFileName, "w"); for (int i = 0; i < n; ++i) { for (int j = 0; j < n; ++j) { if (Dist[i][j] >= INF) Dist[i][j] = INF; } fwrite(Dist[i], sizeof(int), n, outfile); } fclose(outfile); } int ceil(int a, int b) { return (a + b - 1) / b; } void block_FW(int B) { int round = ceil(n, B); for (int r = 0; r < round; ++r) { printf("%d %d\n", r, round); fflush(stdout); /* Phase 1 */ cal(B, r, r, r, 1, 1); /* Phase 2 */ cal(B, r, r, 0, r, 1); cal(B, r, r, r + 1, round - r - 1, 1); cal(B, r, 0, r, 1, r); cal(B, r, r + 1, r, 1, round - r - 1); /* Phase 3 */ cal(B, r, 0, 0, r, r); cal(B, r, 0, r + 1, round - r - 1, r); cal(B, r, r + 1, 0, r, round - r - 1); cal(B, r, r + 1, r + 1, round - r - 1, round - r - 1); } } void cal( int B, int Round, int block_start_x, int block_start_y, int block_width, int block_height) { int block_end_x = block_start_x + block_height; int block_end_y = block_start_y + block_width; for (int b_i = block_start_x; b_i < block_end_x; ++b_i) { for (int b_j = block_start_y; b_j < block_end_y; ++b_j) { // To calculate B*B elements in the block (b_i, b_j) // For each block, it need to compute B times for (int k = Round * B; k < (Round + 1) * B && k < n; ++k) { // To calculate original index of elements in the block (b_i, b_j) // For instance, original index of (0,0) in block (1,2) is (2,5) for V=6,B=2 int block_internal_start_x = b_i * B; int block_internal_end_x = (b_i + 1) * B; int block_internal_start_y = b_j * B; int block_internal_end_y = (b_j + 1) * B; if (block_internal_end_x > n) block_internal_end_x = n; if (block_internal_end_y > n) block_internal_end_y = n; for (int i = block_internal_start_x; i < block_internal_end_x; ++i) { for (int j = block_internal_start_y; j < block_internal_end_y; ++j) { if (Dist[i][k] + Dist[k][j] < Dist[i][j]) { Dist[i][j] = Dist[i][k] + Dist[k][j]; } } } } } } } 单GPU的CUDA代码
#include
#include #include #include const int INF = (1 << 30) - 1; int vertex_num, edge_num, matrix_size; int *dist; double cal_time(struct timespec start, struct timespec end) {struct timespec temp; if ((end.tv_nsec - start.tv_nsec) < 0) {temp.tv_sec = end.tv_sec - start.tv_sec - 1; temp.tv_nsec = 1000000000 + end.tv_nsec - start.tv_nsec; } else {temp.tv_sec = end.tv_sec - start.tv_sec; temp.tv_nsec = end.tv_nsec - start.tv_nsec; } return temp.tv_sec + (double)temp.tv_nsec / 1000000000.0; } __device__ __host__ size_t index_convert(int i, int j, int row_size) {return i * row_size + j; } void input(char *input_file_path, int &block_factor) {FILE *input_file = fopen(input_file_path, "rb"); fread(&vertex_num, sizeof(int), 1, input_file); fread(&edge_num, sizeof(int), 1, input_file); matrix_size = ceil((double)vertex_num / (double)block_factor) * block_factor; cudaMallocHost((void **)&dist, matrix_size * matrix_size * sizeof(int)); for (int i = 0; i < matrix_size; ++i) {for (int j = 0; j < matrix_size; ++j) {if (i != j) dist[index_convert(i, j, matrix_size)] = INF; else if (i < vertex_num) dist[index_convert(i, j, matrix_size)] = 0; else dist[index_convert(i, j, matrix_size)] = INF; } } int data[3]; for (int i = 0; i < edge_num; ++i) {fread(data, sizeof(int), 3, input_file); dist[index_convert(data[0], data[1], matrix_size)] = data[2]; } fclose(input_file); } void output(char *output_file_path) {FILE *output_file = fopen(output_file_path, "w"); for (int i = 0; i < vertex_num; ++i) {fwrite(&dist[index_convert(i, 0, matrix_size)], sizeof(int), vertex_num, output_file); } fclose(output_file); } __constant__ int size[3]; //matrix size, block_factor, grid_size __global__ void phase1(int *d_dist, int round) {__shared__ int share[4 * 1024]; int i = threadIdx.y; int j = threadIdx.x; int i_offset = size[1] * round; int j_offset = size[1] * round; share[index_convert(j, i, size[1])] = d_dist[index_convert(i_offset + i, j_offset + j, size[0])]; #pragma unroll 32 for (int k = 0; k < size[1]; ++k) {__syncthreads(); if (share[index_convert(j, i, size[1])] > share[index_convert(j, k, size[1])] + share[index_convert(k, i, size[1])]) share[index_convert(j, i, size[1])] = share[index_convert(j, k, size[1])] + share[index_convert(k, i, size[1])]; } d_dist[index_convert(i_offset + i, j_offset + j, size[0])] = share[index_convert(j, i, size[1])]; } __global__ void phase2(int *d_dist, int round) {__shared__ int share[3 * 4 * 1024]; int i = threadIdx.y; int j = threadIdx.x; int i_offset, j_offset; if (blockIdx.x == 0) {i_offset = size[1] * ((round + blockIdx.y + 1) % size[2]); j_offset = size[1] * round; share[index_convert(i, j, size[1])] = d_dist[index_convert(i_offset + i, j_offset + j, size[0])]; share[index_convert(i + size[1], j, size[1])] = share[index_convert(i, j, size[1])]; share[index_convert(i + 2 * size[1], j, size[1])] = d_dist[index_convert(j_offset + i, j_offset + j, size[0])]; } else {i_offset = size[1] * round; j_offset = size[1] * ((round + blockIdx.y + 1) % size[2]); share[index_convert(i, j, size[1])] = d_dist[index_convert(i_offset + i, j_offset + j, size[0])]; share[index_convert(i + size[1], j, size[1])] = d_dist[index_convert(i_offset + i, i_offset + j, size[0])]; share[index_convert(i + 2 * size[1], j, size[1])] = share[index_convert(i, j, size[1])]; } #pragma unroll 32 for (int k = 0; k < size[1]; ++k) {__syncthreads(); if (share[index_convert(i, j, size[1])] >share[index_convert(i + size[1], k, size[1])] + share[index_convert(k + 2 * size[1], j, size[1])]) share[index_convert(i, j, size[1])] = share[index_convert(i + size[1], k, size[1])] + share[index_convert(k + 2 * size[1], j, size[1])]; } d_dist[index_convert(i_offset + i, j_offset + j, size[0])] = share[index_convert(i, j, size[1])]; } __global__ void phase3(int *d_dist, int round) {__shared__ int share[3 * 4 * 1024]; int i = threadIdx.y; int j = threadIdx.x; int i_offset = size[1] * ((round + blockIdx.y + 1) % size[2]); int j_offset = size[1] * ((round + blockIdx.x + 1) % size[2]); int r_offset = size[1] * round; share[index_convert(i, j, size[1])] = d_dist[index_convert(i_offset + i, j_offset + j, size[0])]; share[index_convert(i + size[1], j, size[1])] = d_dist[index_convert(i_offset + i, r_offset + j, size[0])]; share[index_convert(i + 2 * size[1], j, size[1])] = d_dist[index_convert(r_offset + i, j_offset + j, size[0])]; #pragma unroll 32 for (int k = 0; k < size[1]; ++k) {__syncthreads(); if (share[index_convert(i, j, size[1])] >share[index_convert(i + size[1], k, size[1])] + share[index_convert(k + 2 * size[1], j, size[1])]) share[index_convert(i, j, size[1])] = share[index_convert(i + size[1], k, size[1])] + share[index_convert(k + 2 * size[1], j, size[1])]; } d_dist[index_convert(i_offset + i, j_offset + j, size[0])] = share[index_convert(i, j, size[1])]; } int main(int argc, char **argv) {double total_time, bfd_time; timespec total_time1, total_time2, bfd_time1, bfd_time2; clock_gettime(CLOCK_MONOTONIC, &total_time1); cudaSetDevice(0); // 设置运行的为第0块GPU int block_factor = 32; if (argc == 4) block_factor = atoi(argv[3]); input(argv[1], block_factor); // 读取数据并初始化dist int grid_size = matrix_size / block_factor; // 划分后的网格大小N = [n / b] int size_info[3] = {matrix_size, block_factor, grid_size}; // n, b, N = [n / b] cudaMemcpyToSymbol(size, size_info, 3 * sizeof(int)); // 将矩阵大小、块大小和网格大小的信息传递给CUDA设备 int *d_dist; clock_gettime(CLOCK_MONOTONIC, &bfd_time1); cudaMalloc(&d_dist, (size_t)sizeof(int) * matrix_size * matrix_size); // 在GPU上分配内存 // 在GPU上分配和复制内存,将距离矩阵dist从主机(CPU)内存拷贝到设备(GPU)内存 cudaMemcpy(d_dist, dist, (size_t)sizeof(int) * matrix_size * matrix_size, cudaMemcpyHostToDevice); // 定义了CUDA的线程块和网格的维度 dim3 block(block_factor, block_factor); // (b, b) dim3 grid2(2, grid_size - 1); // (2, N - 1) dim3 grid3(grid_size - 1, grid_size - 1); // (N - 1, N - 1) for (int r = 0; r < grid_size; ++r) {phase1<<<1, block>>>(d_dist, r); phase2<< >>(d_dist, r); phase3<< >>(d_dist, r); } cudaMemcpy(dist, d_dist, (size_t)sizeof(int) * matrix_size * matrix_size, cudaMemcpyDeviceToHost); clock_gettime(CLOCK_MONOTONIC, &bfd_time2); output(argv[2]); cudaFree(d_dist); cudaFree(dist); clock_gettime(CLOCK_MONOTONIC, &total_time2); bfd_time = cal_time(bfd_time1, bfd_time2); total_time = cal_time(total_time1, total_time2); printf(" vertex: %d\n", vertex_num); printf(" I/O time: %.5f\n", total_time - bfd_time); printf(" cal time: %.5f\n", bfd_time); printf(" runtime: %.5f\n", total_time); return 0; } 2个GPU代码
#include
#include #include #include #include const int INF = (1 << 30) - 1; int vertex_num, edge_num, matrix_size; int *dist; double cal_time(struct timespec start, struct timespec end) {struct timespec temp; if ((end.tv_nsec - start.tv_nsec) < 0) {temp.tv_sec = end.tv_sec - start.tv_sec - 1; temp.tv_nsec = 1000000000 + end.tv_nsec - start.tv_nsec; } else {temp.tv_sec = end.tv_sec - start.tv_sec; temp.tv_nsec = end.tv_nsec - start.tv_nsec; } return temp.tv_sec + (double)temp.tv_nsec / 1000000000.0; } __device__ __host__ size_t index_convert(int i, int j, int row_size) {return i * row_size + j; } void input(char *input_file_path, int block_factor) {FILE *input_file = fopen(input_file_path, "rb"); fread(&vertex_num, sizeof(int), 1, input_file); fread(&edge_num, sizeof(int), 1, input_file); matrix_size = ceil((double)vertex_num / (double)block_factor) * block_factor; cudaMallocHost((void **)&dist, matrix_size * matrix_size * sizeof(int)); for (int i = 0; i < matrix_size; ++i) {for (int j = 0; j < matrix_size; ++j) {if (i != j) dist[index_convert(i, j, matrix_size)] = INF; else if (i < vertex_num) dist[index_convert(i, j, matrix_size)] = 0; else dist[index_convert(i, j, matrix_size)] = INF; } } int data[3]; for (int i = 0; i < edge_num; ++i) {fread(data, sizeof(int), 3, input_file); dist[index_convert(data[0], data[1], matrix_size)] = data[2]; } fclose(input_file); } void output(char *output_file_path) {FILE *output_file = fopen(output_file_path, "w"); for (int i = 0; i < vertex_num; ++i) {fwrite(&dist[index_convert(i, 0, matrix_size)], sizeof(int), vertex_num, output_file); } fclose(output_file); } __constant__ int size[3]; //matrix size, block_factor, grid_size __global__ void phase1(int *d_dist, int round) {__shared__ int pivot[1024]; int i = threadIdx.y; int j = threadIdx.x; int i_offset = 32 * round; int j_offset = 32 * round; pivot[index_convert(i, j, 32)] = d_dist[index_convert(i_offset + i, j_offset + j, size[0])]; #pragma unroll 32 for (int k = 0; k < 32; ++k) {__syncthreads(); if (pivot[index_convert(i, j, 32)] > pivot[index_convert(i, k, 32)] + pivot[index_convert(k, j, 32)]) pivot[index_convert(i, j, 32)] = pivot[index_convert(i, k, 32)] + pivot[index_convert(k, j, 32)]; } d_dist[index_convert(i_offset + i, j_offset + j, size[0])] = pivot[index_convert(i, j, 32)]; } __global__ void phase2(int *d_dist, int round) {__shared__ int self[1024], pivot[1024]; int i = threadIdx.y; int j = threadIdx.x; int i_offset, j_offset; if (blockIdx.x == 0 && blockIdx.y != round) {i_offset = 32 * blockIdx.y; j_offset = 32 * round; self[index_convert(i, j, 32)] = d_dist[index_convert(i_offset + i, j_offset + j, size[0])]; pivot[index_convert(i, j, 32)] = d_dist[index_convert(j_offset + i, j_offset + j, size[0])]; #pragma unroll 32 for (int k = 0; k < 32; ++k) {__syncthreads(); if (self[index_convert(i, j, 32)] > self[index_convert(i, k, 32)] + pivot[index_convert(k, j, 32)]) self[index_convert(i, j, 32)] = self[index_convert(i, k, 32)] + pivot[index_convert(k, j, 32)]; } d_dist[index_convert(i_offset + i, j_offset + j, size[0])] = self[index_convert(i, j, 32)]; } else if (blockIdx.y != round) {i_offset = 32 * round; j_offset = 32 * blockIdx.y; self[index_convert(i, j, 32)] = d_dist[index_convert(i_offset + i, j_offset + j, size[0])]; pivot[index_convert(i, j, 32)] = d_dist[index_convert(i_offset + i, i_offset + j, size[0])]; #pragma unroll 32 for (int k = 0; k < 32; ++k) {__syncthreads(); if (self[index_convert(i, j, 32)] > pivot[index_convert(i, k, 32)] + self[index_convert(k, j, 32)]) self[index_convert(i, j, 32)] = pivot[index_convert(i, k, 32)] + self[index_convert(k, j, 32)]; } d_dist[index_convert(i_offset + i, j_offset + j, size[0])] = self[index_convert(i, j, 32)]; } } __global__ void phase3(int *d_dist, int round, int grid_offset) {__shared__ int col[1024], row[1024]; int self; int block_i = grid_offset + blockIdx.y; int block_j = blockIdx.x; if (block_i == round || block_j == round) return; int i = threadIdx.y; int j = threadIdx.x; int i_offset = 32 * block_i; int j_offset = 32 * block_j; int r_offset = 32 * round; self = d_dist[index_convert(i_offset + i, j_offset + j, size[0])]; col[index_convert(i, j, 32)] = d_dist[index_convert(i_offset + i, r_offset + j, size[0])]; row[index_convert(i, j, 32)] = d_dist[index_convert(r_offset + i, j_offset + j, size[0])]; #pragma unroll 32 for (int k = 0; k < 32; ++k) {__syncthreads(); if (self > col[index_convert(i, k, 32)] + row[index_convert(k, j, 32)]) self = col[index_convert(i, k, 32)] + row[index_convert(k, j, 32)]; } d_dist[index_convert(i_offset + i, j_offset + j, size[0])] = self; } int main(int argc, char **argv) {const int block_factor = 32, device_num = 2; input(argv[1], block_factor); int grid_size = matrix_size / block_factor; int *d_dist[2]; #pragma omp parallel num_threads(device_num) {int device_id = omp_get_thread_num(); cudaSetDevice(device_id); int size_info[3] = {matrix_size, block_factor, grid_size}; cudaMemcpyToSymbol(size, size_info, 3 * sizeof(int)); int grid_partition = grid_size / device_num; int grid_offset = device_id * grid_partition; int grid_count = grid_partition; if (device_id == device_num - 1) grid_count += grid_size % device_num; size_t grid_start = grid_offset * block_factor * matrix_size; cudaMalloc(&(d_dist[device_id]), (size_t)sizeof(int) * matrix_size * matrix_size); #pragma omp barrier cudaMemcpy(&(d_dist[device_id][grid_start]), &(dist[grid_start]), (size_t)sizeof(int) * block_factor * grid_count * matrix_size, cudaMemcpyHostToDevice); dim3 block(block_factor, block_factor); dim3 grid2(2, grid_size); dim3 grid3(grid_size, grid_count); for (int r = 0; r < grid_size; ++r) {if (grid_offset <= r && r < grid_offset + grid_count) {size_t copy_start = r * block_factor * matrix_size; if (device_id == 0) cudaMemcpy(&(d_dist[1][copy_start]), &(d_dist[0][copy_start]), (size_t)sizeof(int) * block_factor * matrix_size, cudaMemcpyDeviceToDevice); else cudaMemcpy(&(d_dist[0][copy_start]), &(d_dist[1][copy_start]), (size_t)sizeof(int) * block_factor * matrix_size, cudaMemcpyDeviceToDevice); } #pragma omp barrier phase1<<<1, block>>>(d_dist[device_id], r); phase2<< >>(d_dist[device_id], r); phase3<< >>(d_dist[device_id], r, grid_offset); } cudaMemcpy(&(dist[grid_start]), &(d_dist[device_id][grid_start]), (size_t)sizeof(int) * block_factor * grid_count * matrix_size, cudaMemcpyDeviceToHost); cudaFree(d_dist[omp_get_thread_num()]); #pragma omp barrier } output(argv[2]); cudaFree(dist); return 0; } Reference
- https://zh.wikipedia.org/wiki/Floyd-Warshall%E7%AE%97%E6%B3%95
- Blocked United Algorithm for the All-Pairs Shortest Paths Problem on Hybrid CPU-GPU Systems
- https://github.com/EricLu1218/Parallel_Programming
- 以下代码均来自:https://github.com/EricLu1218/Parallel_Programming
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- 针对APSP问题的分块联合算法
- 该算法是为在CPU-GPU混合系统上实现高GPU利用率的快速APSP解决方案而设计的。
- 输出一对顶点
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(i,j)之间最短路径的中间顶点的递归过程